The number of molecules in 44.8 L of nitrogen at exactly 0 $\circ$ C and 3.00 atm is A)1.20 * 10²⁴ B)3.61 * 10²⁴ C)3.61 * 10^-23 D)2.01 * 10²³ E)18.0 * 10^-²³

Question

Quizplus · Accepted Answer

Using the ideal gas law, PV = nRT, where P = 3.00 atm, V = 44.8 L, R = 0.0821 L·atm/mol·K, and T = 273 K (0°C), we can calculate the number of moles (n). Then, multiply by Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules.

The Number of Molecules in 44 ∘\circ∘ C and 3

The Number of Molecules in 44 $\circ$ C and 3