If the scattering angle of the light in Compton's scattering experiment is 90°,what is the change in the wavelength of the light? (m_electron = 9.11 × 10^-31 kg,c = 3.00 × 10⁸ m/s,h = 6.626 × 10^-34 J ∙ s) A)1.22 × 10^-12 m B)2.42 × 10^-12 m C)3.65 × 10^-12 m D)4.85 × 10^-12 m

Question

Quizplus · Accepted Answer

The change in wavelength of the scattered light in Compton's scattering experiment can be calculated using the formula:
Δλ = λ' - λ = h/mc (1 - cosθ)
where λ is the wavelength of the incident light, λ' is the wavelength of the scattered light, θ is the scattering angle, h is the Planck's constant, m is the mass of the electron, and c is the speed of light.

Substituting the given values, we get:
Δλ = h/mc (1 - cosθ)
Δλ = (6.626 × 10^-34 J ∙ s)/(9.11 × 10^-31 kg × 3.00 × 10^8 m/s) (1 - cos 90°)
Δλ = 2.42 × 10^-12 m

Therefore, the best choice is B, which gives the value of the change in wavelength as 2.42 × 10^-12 m.

If the Scattering Angle of the Light in Compton's Scattering