What is the energy (in eV)of an optical photon of frequency $6.43 \times 10 ^ { 14 } \mathrm {~Hz}$ (h = 6.626 × 10^-34 J ∙ s,1 eV = 1.60 × 10^-19 J) A)2.66 eV B)1.62 eV C)1.94 eV D)3.27 eV

Question

Quizplus · Accepted Answer

The energy of a photon is given by:

E = hf

where h is the Planck's constant (6.626 × 10-34 J ∙ s) and f is the frequency of the photon.

Converting the frequency to Hz:

f = 6.43 × 1014 Hz

Plugging in the values:

E = hf = (6.626 × 10-34 J ∙ s) × (6.43 × 1014 Hz) = 4.26 × 10-19 J

Converting the energy to eV:

1 eV = 1.60 × 10-19 J

E = (4.26 × 10-19 J) / (1.60 × 10-19 J/eV) = 2.66 eV

Therefore, the energy of the optical photon is 2.66 eV, which corresponds to choice A.

What Is the Energy (In EV)of an Optical Photon of Frequency