An organ pipe open at both ends has a length of 0.80 m.If the velocity of sound in air is $340 \mathrm {~m} / \mathrm { s } \text {, }$ what is the frequency of the second harmonic of this pipe?
A)213 Hz
B)425 Hz
C)638 Hz
D)850 Hz

Question

Quizplus · Accepted Answer

The second harmonic of an organ pipe open at both ends corresponds to the first overtone, which has a wavelength equal to the length of the pipe. The formula for frequency is $f = \frac{v}{\lambda}$, where $v$ is the velocity of sound and $\lambda$ is the wavelength. For the second harmonic, $\lambda = \frac{2L}{2}$ (where $L$ is the length of the pipe), so $\lambda = L = 0.80 m$. Therefore, $f = \frac{340 m/s}{0.80 m} = 425 Hz$.

An Organ Pipe Open at Both Ends Has a Length 340 m/s, 340 \mathrm {~m} / \mathrm { s } \text {, }340 m/s,

An Organ Pipe Open at Both Ends Has a Length $340 \mathrm {~m} / \mathrm { s } \text {, }$