The coil of an ac generator has 50 loops and a cross-sectional area of 0.25 m².What is the maximum emf that can be generated by this generator if it is spinning with an angular speed of 4.0 rad/s in a 2.0-T $\vec { B }$ field? A)50 V B)100 V C)200 V D)400 V

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Quizplus · Accepted Answer

The maximum emf ($ \varepsilon_{max} $) generated by an AC generator can be calculated using the formula: $ \varepsilon_{max} = NBA\omega $, where $N$ is the number of loops, $B$ is the magnetic field strength, $A$ is the cross-sectional area of the coil, and $\omega$ is the angular speed. Substituting the given values: $ \varepsilon_{max} = 50 \times 2.0 \times 0.25 \times 4.0 = 100 $ V.

The Coil of an Ac Generator Has 50 Loops and a Cross-Sectional