If the power rating of a 400-Ω resistor is 0.800 W,what is the maximum voltage that can safely be connected across the resistor?
A)110 V
B)17.9 V
C)170 V
D)1.80 V

Question

Quizplus · Accepted Answer

Using the formula P = V^2 / R, we can solve for the maximum voltage:

0.800 W = V^2 / 400 Ω
V^2 = 320
V = 17.9 V (rounded to one decimal place)

Therefore, the maximum voltage that can safely be connected across the resistor is 17.9 V. Choice B is correct.

If the Power Rating of a 400-Ω Resistor Is 0