A tube of mercury with resistivity 9.84 × 10^-7 Ω ∙ m has a uniform electric field of 23 N/C inside the mercury.What is the current through the tube,if the radius of the tube is 0.495 mm? A)18 A B)180 A C)29 A D)280 A

Question

Quizplus · Accepted Answer

The formula for electric current is given by:
I = (πr^2)J
where,
π = pi
r = radius of the tube
J = electric field/resistivity

Substitute the given values in the formula, we get:
I = (π × (0.495 × 10^-3)^2) × (23/(9.84 × 10^-7))
I ≈ 18 A

Therefore, the answer is A) 18 A.

A Tube of Mercury with Resistivity 9