What force does the water exert (in addition to that due to atmospheric pressure)on a submarine window of radius 44.0 cm at a depth of 9,400 m in sea water? The density of sea water is 1025 kg/m³. A)5.74 × 10⁷_N B)5.74 × 10¹¹_N C)2.87 × 10¹¹_N D)1.83 × 10⁷_N E)2.87 × 10⁷_N

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Quizplus · Accepted Answer

The force exerted by the water on the submarine window can be calculated using the formula for pressure due to a fluid column, $P = \rho gh$, and then applying the force equation $F = PA$, where $P$ is the pressure, $\rho$ is the density of the fluid, $g$ is the acceleration due to gravity, $h$ is the depth, $F$ is the force, and $A$ is the area of the window. Given the density of sea water ($1025 \, \text{kg/m}^3$), the depth ($9400 \, \text{m}$), and the radius of the window ($0.44 \, \text{m}$), we can calculate the additional force due to the water pressure. The correct calculation leads to the force value closest to the option A, $5.74 \times 10^{7} \, \text{N}$.

What Force Does the Water Exert (In Addition to That