A force of $16.88 \mathrm {~N}$ is exerted tangentially to a wheel of radius 0.340 m and causes an angular acceleration of 1.20 rad/s².What is the moment of inertia of the wheel? A)4.78 kg ∙ m² B)3.59 kg ∙ m² C)5.98 kg ∙ m² D)7.17 kg ∙ m²

Question

Quizplus · Accepted Answer

The torque τ is given by τ = r * F = 0.340 m * 16.88 N = 5.7392 Nm. The moment of inertia I is τ / α = 5.7392 Nm / 1.20 rad/s² = 4.7827 kg∙m², which rounds to 4.78 kg∙m².

A Force Of 16.88 N16.88 \mathrm {~N}16.88 N Is Exerted Tangentially to a Wheel of Radius 0

A Force Of $16.88 \mathrm {~N}$ Is Exerted Tangentially to a Wheel of Radius 0