An ideal spring has a spring constant of 60 N/m.How much energy does it store when it is stretched by 1.0 cm?
A)0.0030 J
B)0.30 J
C)60 J
D)600 J

Question

Quizplus · Accepted Answer

The energy stored in a spring is given by the formula $E = \frac{1}{2}kx^2$, where $E$ is the energy in joules, $k$ is the spring constant in N/m, and $x$ is the displacement in meters. Here, $k = 60$ N/m and $x = 1.0$ cm = 0.01 m. Plugging these values into the formula gives $E = \frac{1}{2} \times 60 \times (0.01)^2 = 0.003$ J.

An Ideal Spring Has a Spring Constant of 60 N/m