Find the orbital speed of an ice cube in the rings of Saturn.The mass of Saturn is 5.68 x 10²⁶ kg,and use an orbital radius of 1.00 x 10⁵ km.(G = 6.67 × 10^-11 N ∙ m²/kg²) A)19.5 km/s B)27.5 km/s C)13.8 km/s D)9.40 km/s

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Quizplus · Accepted Answer

The orbital speed of an object is given by:$$v = \sqrt{\frac{GM}{r}}$$where:* v is the orbital speed in m/s* G is the gravitational constant in N ∙ m^2/kg^2* M is the mass of the object in kg* r is the orbital radius in mPlugging in the given values, we get:$$v = \sqrt{\frac{(6.67 × 10^{-11} N ∙ m^2/kg^2)(5.68 × 10^{26} kg)}{1.00 × 10^5 km}}$$$$v = 19.5 km/s$$Therefore, the correct answer is A.

Find the Orbital Speed of an Ice Cube in the Rings