P(X = 6); n = 13,p = 0.5
A) 0.2095
B) 0.3142
C) 0.2723
D) 0.0156

Name: P(X = 6); n = 13,p = 0.5 A) 0.2095 B) 0.3142 C) 0.2723 D) 0.0156
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Quizplus · Accepted Answer

The probability of getting exactly 6 successes in 13 trials with a success probability of 0.5 in each trial can be calculated using the binomial probability formula: $P(X = k) = \binom{n}{k}p^k(1-p)^{n-k}$. Plugging in the values $n = 13$, $k = 6$, and $p = 0.5$, we get $P(X = 6) \approx 0.2095$.

P(X = 6); N = 13,p = 0.5