As shown in the figure,a small particle of charge q = -7.0 × 10^-6 C and mass m = 3.1 × 10^-12 kg has velocity v₀ = 9.4 × 10³ m/s as it enters a region of uniform magnetic field.The particle is observed to travel in the semicircular path shown,with radius R = 5.0 cm.Calculate the magnitude and direction of the magnetic field in the region.

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The Answer of As shown in the figure,a small particle of charge q = -7.0 × 10^-6 C and mass m = 3.1 × 10^-12 kg has velocity v₀ = 9.4 × 10³ m/s as it enters a region of uniform magnetic field.The particle is observed to travel in the semicircular path shown,with radius R = 5.0 cm.Calculate the magnitude and direction of the magnetic field in the region.

As Shown in the Figure,a Small Particle of Charge Q