A conducting sphere is charged up such that the potential on its surface is 100 V (relative to infinity).If the sphere's radius were twice as large,but the charge on the sphere were the same,what would be the potential on the surface relative to infinity?
A) 50 V
B) 25 V
C) 100 V
D) 200 V

Question

Quizplus · Accepted Answer

The potential on the surface of a conducting sphere is given by $V = \frac{kQ}{r}$, where $V$ is the potential, $k$ is Coulomb's constant, $Q$ is the charge on the sphere, and $r$ is the radius of the sphere. Doubling the radius while keeping the charge constant halves the potential, making it 50 V.

A Conducting Sphere Is Charged Up Such That the Potential