A turbine blade rotates with angular velocity ω(t)= 2.00 rad/s- 2.1.00 rad/s³t².What is the angular acceleration of the blade at t = 9.10 s? A) -38.2 rad/s² B) -19.1 rad/s² C) -86.0 rad/s² D) -36.2 rad/s² E) -172 rad/s²

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Explanation:The angular acceleration is the derivative of the angular velocity with respect to time:$$\alpha(t)=\frac{d\omega(t)}{dt}=\frac{d}{dt}(2.00	ext{ rad/s}-2.100	ext{ rad/s}^3t^2)$$$$=-4.200	ext{ rad/s}^3t$$At t = 9.10 s, the angular acceleration is:$$\alpha(9.10	ext{ s})=-4.200	ext{ rad/s}^3(9.10	ext{ s})=-38.2	ext{ rad/s}^2$$

A Turbine Blade Rotates with Angular Velocity ω(T)= 2