A diatomic molecule is vibrating in its first excited quantum state above the ground state.In that excited state,its frequency is 2.0 × 10¹³ Hz.What is the energy of the molecule in this state? (h = 6.626 × 10^-34 J • s,h = 1.055 × 10^-34 J • s,1 eV = 1.60 × 10^-19 J A) 0.041 eV B) 0.083 eV C) 0.12 eV D) 0.15 eV E) 0.17 eV

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The Answer of A diatomic molecule is vibrating in its first excited quantum state above the ground state.In that excited state,its frequency is 2.0 × 10¹³ Hz.What is the energy of the molecule in this state? (h = 6.626 × 10^-34 J • s,h = 1.055 × 10^-34 J • s,1 eV = 1.60 × 10^-19 J A) 0.041 eV B) 0.083 eV C) 0.12 eV D) 0.15 eV E) 0.17 eV

A Diatomic Molecule Is Vibrating in Its First Excited Quantum