As shown in the figure,an insulated wire is bent into a circular loop of radius 6.0 cm and has two long straight sections.The loop is in the xy-plane,with the center at the origin.The straight sections are parallel to the z-axis.The wire carries a current of 8.0 A.What is the magnitude of the magnetic field at the origin? (μ₀ = 4π × 10^-7 T • m/A) A) 75 µT B) 81 µT C) 88 µT D) 110 µT E) 120 µT

Question

Quizplus · Accepted Answer

The formula for magnetic field at the center of a circular loop is given as:
B = μ0I/2r
Where μ0 is the magnetic constant, I is the current, and r is the radius of the loop.

Here, the current is given as 8.0 A and the radius is 6.0 cm(0.06 m)
So, substituting the values in the above formula, we get
B = (4π × 10^-7 T • m/A) × 8.0 A / (2 × 0.06 m)
B = 226.2 µT or 0.2262 mT

Therefore, the magnitude of magnetic field at the origin is 88 µT(approximately) which is given by option C.

As Shown in the Figure,an Insulated Wire Is Bent into a Circular