Calculate the K_sp for silver carbonate if the solubility of Ag₂CO₃ in pure water is 3.5 × 10^-2g L^-1. A)2.1 × 10^-12 B)8.2 × 10^-12 C)1.6 × 10^-8 D)3.2 × 10^-8

Question

Quizplus · Accepted Answer

First, convert the solubility from g/L to mol/L using the molar mass of Ag2CO3 (275.75 g/mol). Solubility in mol/L = 3.5 × 10^-2 g/L ÷ 275.75 g/mol = 1.27 × 10^-4 mol/L. The dissolution of Ag2CO3 is Ag2CO3(s) ⇌ 2Ag+(aq) + CO3^2-(aq), so [Ag+] = 2 × 1.27 × 10^-4 mol/L and [CO3^2-] = 1.27 × 10^-4 mol/L. Ksp = [Ag+]^2[CO3^2-] = (2 × 1.27 × 10^-4)^2 × 1.27 × 10^-4 = 8.2 × 10^-12.

Calculate the Ksp for Silver Carbonate If the Solubility of Ag2CO3

Calculate the K_sp for Silver Carbonate If the Solubility of Ag₂CO₃