Calculate the concentration of bicarbonate ion,HCO₃^-,in a 0.010 mol L^-1 H₂CO₃ solution that has the stepwise dissociation constants K_a1 = 4.3 × 10^-7 and K_a2 = 5.6 × 10^-1¹. A)6.6 × 10^-⁵ mol L^-1 B)4.3 × 10^-7 mol L^-1 C)4.3 × 10^-⁹ mol L^-1 D)5.6 × 10^-11 mol L^-1

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The correct answer is A because the concentration of bicarbonate ion, HCO3-, in a 0.010 mol L-1 H2CO3 solution that has the stepwise dissociation constants Ka1 = 4.3 × 10-7 and Ka2 = 5.6 × 10-11 is 6.6 × 10-5 mol L-1. This can be calculated using the following equation:[HCO3-] = Ka1 * [H2CO3] / [H+]where Ka1 is the first dissociation constant, [H2CO3] is the concentration of carbonic acid, and [H+] is the concentration of hydrogen ions.Substituting the given values into this equation, we get:[HCO3-] = (4.3 × 10-7) * (0.010 mol L-1) / (10-7) = 6.6 × 10-5 mol L-1

Calculate the Concentration of Bicarbonate Ion,HCO3-,in a 0

Calculate the Concentration of Bicarbonate Ion,HCO₃^-,in a 0