Determine the [OH^-] concentration of a 0.116 mol L^-¹ Ba(OH)₂ solution at 25 °C. A)4.310 × 10^-14 mol L^-1 B)0.116 mol L^-1 C)0.232 mol L^-1 D)8.62 × 10^-14 mol L^-1 E)0.058 mol L^-1

Question

Quizplus · Accepted Answer

To find the [OHS1U1P1-S1S1P0] concentration, we need to first write the balanced equation for the reaction between Ba(OH)S1U1B12S1U1B0 and LS1U1P1-S1S1P0S1U1P11S1S1P0. The equation is:

Ba(OH)S1U1B12S1U1B0 + LS1U1P1-S1S1P0S1U1P11S1S1P0 -> LS1U1P1-S1S1P0 + BaS1U1B12S1U1B0 + H2OS1U1P1

From this equation, we see that 1 mole of Ba(OH)S1U1B12S1U1B0 reacts with 1 mole of LS1U1P1-S1S1P0S1U1P11S1S1P0 to produce 1 mole of LS1U1P1-S1S1P0.

The number of moles of Ba(OH)S1U1B12S1U1B0 in the solution can be calculated using the formula:

moles of Ba(OH)S1U1B12S1U1B0 = concentration of Ba(OH)S1U1B12S1U1B0 x volume of solution

Substituting the values given in the question, we get:

moles of Ba(OH)S1U1B12S1U1B0 = 0.116 mol LS1U1P1-S1S1P0 x 0.232 L = 0.026912 mol LS1U1P1-S1S1P0

Since 1 mole of Ba(OH)S1U1B12S1U1B0 reacts with 1 mole of LS1U1P1-S1S1P0S1U1P11S1S1P0 to produce 1 mole of LS1U1P1-S1S1P0, the concentration of LS1U1P1-S1S1P0 in the solution is also 0.026912 mol LS1U1P1-S1S1P0 / 0.232 L = 0.116 mol LS1U1P1-1S1S1P0. Therefore, the correct answer is C.

Determine the [OH-] Concentration of a 0

Determine the [OH^-] Concentration of a 0