Calculate the pOH of a solution that contains 2.4 × 10^-5 mol L^-1 H₃O⁺ at 25 °C. A)2.40 B)9.38 C)4.62 D)11.60 E)4.17

Name: Calculate the pOH of a solution that contains 2.4 × 10 -5 mol L -1 H 3 O + at 25 °C. A)2.40 B)9.38 C)4.62 D)11.60 E)4.17
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Quizplus · Accepted Answer

The pH of the solution is calculated using the formula pH = -log[H3O+]. For [H3O+] = 2.4 × 10^-5, pH = -log(2.4 × 10^-5) = 4.62. Since pH + pOH = 14 at 25 °C, pOH = 14 - 4.62 = 9.38.

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