Place the following ions in order of decreasing radius. Te²^- $\quad$F^- $\quad$O²^- A)F^- O²^- Te²^- B)F^- Te²^- O²^- C)Te²^- O²^- F^- D)Te²^- F^- O²^- E)O²^- F^- Te²^-

Question

Place the following ions in order of decreasing radius. Te²^- $\quad$F^- $\quad$O²^- A)F^- > O²^- > Te²^- B)F^- > Te²^- > O²^- C)Te²^- > O²^- > F^- D)Te²^- > F^- > O²^- E)O²^- > F^- > Te²^-

Quizplus · Accepted Answer

The trend in radius follows the periodic trend of increasing radius down a group and decreasing radius across a period. The ions listed can be arranged in the order Te²^- > O²^- > F^-. This is because Te has the largest atomic radius, and the addition of electrons and sulfur atoms does not significantly decrease its radius. Meanwhile, F has the smallest atomic radius, and the addition of electrons and sulfur atoms decreases its radius significantly. Therefore, the correct order is Te²^- > O²^- > F^-.

Place the Following Ions in Order of Decreasing Radius \quad F- \quad

Place the Following Ions in Order of Decreasing Radius $\quad$ F^- $\quad$