What is the temperature if krypton has a root mean square velocity of 348 m $s ^ { - 1 }$ ?
A)800°C
B)791°C
C)134°C
D)604°C
E)596°C

Question

Quizplus · Accepted Answer

The root mean square velocity (rms) of atoms is given by the equation rms velocity = √(3kT/m), where k is the Boltzmann constant, T is the temperature in Kelvin and m is the mass of the atom. 
Rearranging this equation for T, we get T = (m * rms velocity^2)/(3k). 
For krypton, m is approximately equal to 83.80 u (atomic mass units) or 1.40 × 10^-25 kg. 
Substituting this into the equation and converting the velocity to SI units, we get T = (1.40 × 10^-25 kg * (348 m/s)^2)/(3 * 1.38 × 10^-23 J/K) ≈ 134°C. Hence, the correct answer is option C.

What Is the Temperature If Krypton Has a Root Mean s−1s ^ { - 1 }s−1

What Is the Temperature If Krypton Has a Root Mean $s ^ { - 1 }$