A wire carrying a current is shaped in the form of a circular loop of radius 4.0 mm. If the magnetic field strength at its center is $1.1 \mathrm { mT }$ with no external magnetic fields present, what is the magnitude of the current flowing through the wire? (μ₀ = 4π × 10^-7 T ∙ m/A) A) 7.0 A B) 28 A C) 14 A D) 17 A

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The magnetic field strength at the center of a circular loop of wire is given by:$$B = \frac{\mu_0 I}{2R}$$where:* B is the magnetic field strength (in teslas)* μ0 is the permeability of free space (4π × 10^-7 T ∙ m/A)* I is the current flowing through the wire (in amperes)* R is the radius of the loop (in meters)In this problem, we are given that:* B = 1.1 mT = 1.1 × 10^-3 T* R = 4.0 mm = 4.0 × 10^-3 mSubstituting these values into the equation above, we get:$$1.1 	imes 10^{-3} \mathrm{T} = \frac{4\pi 	imes 10^{-7} \mathrm{T} \cdot \mathrm{m/A} 	imes I}{2 	imes 4.0 	imes 10^{-3} \mathrm{m}}$$Solving for I, we get:$$I = \frac{1.1 	imes 10^{-3} \mathrm{T} 	imes 2 	imes 4.0 	imes 10^{-3} \mathrm{m}}{4\pi 	imes 10^{-7} \mathrm{T} \cdot \mathrm{m/A}} = 7.0 \mathrm{A}$$Therefore, the magnitude of the current flowing through the wire is 7.0 A.

A Wire Carrying a Current Is Shaped in the Form 1.1mT1.1 \mathrm { mT }1.1mT

A Wire Carrying a Current Is Shaped in the Form $1.1 \mathrm { mT }$