A 5.0-μF, a 14-μF, and a $21 - \mu \mathrm { F }$ capacitor are connected in parallel. How much capacitance would a single capacitor need to have to replace the three capacitors?
A) 40 μF
B) 21 μF
C) 5.0 μF
D) 14 μF

Question

A 5.0-μF, a 14-μF, and a $21 - \mu \mathrm { F }$ capacitor are connected in parallel. How much capacitance would a single capacitor need to have to replace the three capacitors?
A) 40 μF
B) 21  μF
C) 5.0 μF
D) 14 μF

Quizplus · Accepted Answer

When capacitors are connected in parallel, their capacitances add up. Therefore, the total capacitance is 5.0 μF + 14 μF + 21 μF = 40 μF.

A 50-μF, a 14-μF, and A A 21 21−μF21 - \mu \mathrm { F }21−μF

A 50-μF, a 14-μF, and A A 21 $21 - \mu \mathrm { F }$