In 1851 Jean Bernard Leon Foucault demonstrated the rotation of the earth using a pendulum 11.0 m long,which was set up in the Paris Observatory.How long would it have taken for Foucault's pendulum to make one complete swing back to its starting point if g = 9.81 m/s² at the observatory? A)6.65 s B)5.63 s C)1.79 s D)2.12 s E)2.58 s

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Quizplus · Accepted Answer

The period of a pendulum is given by the formula $T = 2\pi\sqrt{\frac{L}{g}}$, where $L$ is the length of the pendulum and $g$ is the acceleration due to gravity. Substituting $L = 11.0 \, \text{m}$ and $g = 9.81 \, \text{m/s}^2$ into the formula gives $T = 2\pi\sqrt{\frac{11.0}{9.81}} \approx 6.65 \, \text{s}$.

In 1851 Jean Bernard Leon Foucault Demonstrated the Rotation of the Earth