An astronaut has landed on Planet N-40 and conducts an experiment to determine the acceleration due to gravity on that planet.She uses a simple pendulum that is 0.640 m long and measures that 10 complete oscillations 26.0 s.What is the acceleration of gravity on Planet N-40? A)4.85 m/s² B)1.66 m/s² C)3.74 m/s² D)2.39 m/s² E)9.81 m/s²

Question

Quizplus · Accepted Answer

The period of a pendulum is given by T = 2π√(L/g). For 10 oscillations, the total time is 26.0 s, so the period T = 26.0 s / 10 = 2.6 s. Rearranging the formula to solve for g gives g = 4π²L/T². Substituting L = 0.640 m and T = 2.6 s, we find g ≈ 3.74 m/s².

An Astronaut Has Landed on Planet N-40 and Conducts an Experiment