Let P(A ∩B) = 0.3, and P(A ∩ B^c) = 0.15. Compute P(A). A) 0.15 B) 0.30 C) 0.45 D) 0.50

Name: Let P(A ∩B) = 0.3, and P(A ∩ B c ) = 0.15. Compute P(A). A) 0.15 B) 0.30 C) 0.45 D) 0.50
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Given P(A ∩ B) = 0.3 and P(A ∩ B') = 0.15, where B' is the complement of B. Since A can either intersect with B or B', P(A) = P(A ∩ B) + P(A ∩ B') = 0.3 + 0.15 = 0.45.