Consider the following metabolic reaction:
Succinyl-CoA + Acetoacetate $\to$Acetoacetyl-CoA + Succinate $\Delta$G°' = -1.25 kJ/mol
The $\Delta$G°' for the hydrolysis of Succinyl-CoA is -33.9 kJ/mol.What is the $\Delta$G°' for the hydrolysis of Acetoacetyl-CoA: Acetoacetyl-CoA $\to$ Acetoacetate + CoA
A)-35.2 kJ/mol
B)-32.7 kJ/mol
C)+32.7 kJ/mol
D)+35.2 kJ/mol
E)none of the above

Question

Quizplus · Accepted Answer

The overall reaction ΔG°' is -1.25 kJ/mol. Given the ΔG°' for Succinyl-CoA hydrolysis is -33.9 kJ/mol, the ΔG°' for Acetoacetyl-CoA hydrolysis can be calculated by rearranging the equation: -1.25 = (-33.9) + ΔG°' (Acetoacetyl-CoA), resulting in ΔG°' (Acetoacetyl-CoA) = -1.25 + 33.9 = -32.7 kJ/mol.

Consider the Following Metabolic Reaction: Succinyl-CoA + Acetoacetate →\to→ Acetoacetyl-CoA + Succinate

Consider the Following Metabolic Reaction:
Succinyl-CoA + Acetoacetate $\to$ Acetoacetyl-CoA + Succinate