A thin straight wire of uniform density is oriented in the xy-plane.The ends of the wire are located at (x,y)= (-2.00 m,-1.00 m)and (x,y)= (2.00 m,3.00 m).Where is its center of mass located?
A)(x,y)= (0,0)
B)(x,y)= (0,1.00 m)
C)(x,y)= (1.00 m,0)
D)(x,y)= (1.00 m,1.00 m)

Question

Quizplus · Accepted Answer

The center of mass of a uniform straight wire is located at the midpoint of the line segment connecting its ends. The midpoint can be found by averaging the x-coordinates and the y-coordinates of the ends: $x_{cm} = \frac{-2 + 2}{2} = 0$ and $y_{cm} = \frac{-1 + 3}{2} = 1$. Therefore, the center of mass is at (0, 1.00 m).

A Thin Straight Wire of Uniform Density Is Oriented in the Xy-Plane.The