What is the maximum height of a projectile shot at an angle of 25 $\circ$ with respect to the horizontal and initial speed of 22 m/s?
A)8.86 m
B)4.41 m
C)20.28 m
D)10.14 m
E)None are correct.More information is needed.

Question

Quizplus · Accepted Answer

The maximum height of a projectile is given by the formula $ h = \frac{v^2 \sin^2(\theta)}{2g} $. Substituting $ v = 22 \, \text{m/s} $, $ \theta = 25^\circ $, and $ g = 9.81 \, \text{m/s}^2 $, the maximum height is approximately 4.41 m.

What Is the Maximum Height of a Projectile Shot at an Angle