A 1.50-kg ball makes an elastic head-on collision with a 1.00-kg ball.Before the collision,the speed of the 1.50-kg ball is 1.0 m/s,and the speed of the 1.00-kg ball is zero.The speed of the 1.00-kg ball after the collision is
A)greater than 1.0 m/s,but less than 2.0 m/s.
B)2.0 m/s.
C)less than 1 m/s.
D)1 m/s.
E)zero.

Question

Quizplus · Accepted Answer

In an elastic collision, both momentum and kinetic energy are conserved. The final velocity of the 1.00-kg ball can be found using the conservation of momentum and the fact that the collision is elastic. The formula for the final velocity of the second ball (v2') in an elastic collision is given by v2' = [(2*m1)/(m1 + m2)] * v1, where m1 and m2 are the masses of the balls, and v1 is the initial velocity of the first ball. Substituting the given values, we get v2' = [(2*1.50)/(1.50 + 1.00)] * 1.0 = (3/2.5) * 1.0 = 1.2 m/s, which is greater than 1.0 m/s but less than 2.0 m/s.

A 150-Kg Ball Makes an Elastic Head-On Collision with a 1