Consider two carts,of masses m and 2m,at rest on a frictionless air track.You push the first cart for 3 s and then the other for the same length of time and with the same force.The final speed of the cart with mass 2 m is
A)one third the speed of the cart of mass m.
B)one fourth the speed of the cart of mass m.
C)one half the speed of the cart of mass m.
D)the same as the cart of mass m.

Question

Quizplus · Accepted Answer

According to Newton's second law, F = ma. Since both carts experience the same force and are initially at rest, the acceleration of the two carts will be the same. Therefore, the final velocity of each cart will depend on their masses and the time they were pushed. Using the equation vf = vi + at, where vi is the initial velocity (zero) and a is the acceleration, we can derive the formula vf = at. Since the carts experience the same force and have the same acceleration but different masses, the cart with mass 2m will have half the acceleration of the cart with mass m. Therefore, the final velocity of the cart with mass 2m will be half the final velocity of the cart with mass m, or one half the speed of the cart of mass m.

Consider Two Carts,of Masses M and 2m,at Rest on a Frictionless