The radius of curvature of a highway exit is r = 68.5 m.The surface of the exit road is horizontal,not banked.(See figure.)If the static friction between the tires and the surface of the road is µs = 0.688,then what is the maximum speed at which the car can exit the highway safely without sliding? (in m/s) A)1.57 * 10¹ B)1.84 * 10¹ C)2.15 * 10¹ D)2.52 * 10¹ E)2.94 * 10¹

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The Answer of The radius of curvature of a highway exit is r = 68.5 m.The surface of the exit road is horizontal,not banked.(See figure.)If the static friction between the tires and the surface of the road is µs = 0.688,then what is the maximum speed at which the car can exit the highway safely without sliding? (in m/s) A)1.57 * 10¹ B)1.84 * 10¹ C)2.15 * 10¹ D)2.52 * 10¹ E)2.94 * 10¹

The Radius of Curvature of a Highway Exit Is R