A CD-ROM starts from rest and undergoes uniform angular acceleration until it reaches 26,000 rpm in 0.25 s.What is its angular acceleration? A)1.1 * 10⁴ rad/s² B)5.4 * 10³ rad/s² C)1.0 * 10⁵ rad/s² D)6.5 * 10³ rad/s²

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Quizplus · Accepted Answer

The angular acceleration is given by:$$\alpha = \frac{\omega_f - \omega_i}{t}$$where:* $\omega_f$ is the final angular velocity* $\omega_i$ is the initial angular velocity* $t$ is the timeIn this case, $\omega_i = 0$, so:$$\alpha = \frac{\omega_f}{t} = \frac{26,000 \text{ rpm}}{0.25 \text{ s}} = 1.1 \times 10^4 \text{ rad/s}^2$$

A CD-ROM Starts from Rest and Undergoes Uniform Angular Acceleration