A small cube of copper (density = 8930 kg/m3) is used to support a large cube of marble (density = 2560 kg/m3) .The copper cube has sides of length 2.00 cm and is carefully placed on a flat,level table under the center of the cube of marble that has sides of length 30.0 cm.Given that the Young's modulus of copper is 110 GPa,by how much is the copper compressed?
A) 2.0 * 10-8 m
B) 6.8 * 10-8 m
C) 3.1 * 10-8 m
D) 1.1 * 10-6 m
E) 3.6 * 10-6 m
Correct Answer:
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