What is the period of oscillation for a 0.50-kg block which slides on a horizontal,frictionless plane,and is attached to a spring having spring constant 25 N/m?
A)0.13 s
B)0.14 s
C)0.89 s
D)1.1 s
E)7.1 s

Question

Quizplus · Accepted Answer

The period of oscillation $T$ for a mass $m$ attached to a spring with spring constant $k$ is given by the formula $T = 2\pi\sqrt{\frac{m}{k}}$. Plugging in the given values, $m = 0.50 \, \text{kg}$ and $k = 25 \, \text{N/m}$, we get $T = 2\pi\sqrt{\frac{0.50}{25}} \approx 0.89 \, \text{s}$.

What Is the Period of Oscillation for a 0