A 5.00-m long string of mass 10.0 g is clamped at both ends.The tension in the string is 200 N.The string is pluck so that it oscillates and the speed of a wave on the string is 150 m/s.What is the frequency of the wave if it produces a standing wave with 4 antinodes?
A)31 Hz
B)45 Hz
C)60 Hz
D)79 Hz
E)84 Hz

Question

Quizplus · Accepted Answer

The frequency of a standing wave on a string with length L and n antinodes can be found using the equation: 
f = (n/2L) * v, 
where v is the speed of the wave on the string. 
Substituting the given values: 
L = 5.00m 
n = 4 antinodes 
v = 150m/s 
f = (n/2L) * v 
f = (4/2(5.00)) * 150 
f = 60 Hz 
Therefore, the frequency of the wave is 60 Hz, which corresponds to choice C.

A 500-M Long String of Mass 10