Paul stands exactly halfway between two sound sources,one of which emits with twice the power of the other.What is the relative intensity factor (in dB)of the two sources at the point where Paul stands?
A)0 dB
B)1.0 dB
C)2.0 dB
D)3.0 dB
E)4.0 dB

Question

Quizplus · Accepted Answer

The intensity of sound is proportional to the power of the source. If one source emits with twice the power of the other, the intensity ratio is 2:1. The relative intensity in decibels (dB) is calculated using the formula 10 * log10(I1/I2), where I1 and I2 are the intensities. Thus, 10 * log10(2) ≈ 3.0 dB.

Paul Stands Exactly Halfway Between Two Sound Sources,one of Which