An electron in a hydrogen atom experiences a Coulomb force,F = 85.2 * 10^-9 N,as it goes in a circular orbit around the central proton.How far away is the electron from the proton? A)0.052 nm B)52 $\mu$m C)0.35 nm D)35 $\mu$m E)27 mm

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The Coulomb force between an electron and a proton in a hydrogen atom is given by $F = \frac{k \cdot e^2}{r^2}$, where $k = 8.987 \times 10^9 \, \text{N m}^2/\text{C}^2$ (Coulomb's constant), $e = 1.602 \times 10^{-19} \, \text{C}$ (charge of an electron), and $r$ is the distance between the electron and the proton. Solving for $r$ gives a value close to 0.0529 nm, which rounds to 0.052 nm, indicating the typical scale of atomic dimensions.

An Electron in a Hydrogen Atom Experiences a Coulomb Force,F μ\muμ

An Electron in a Hydrogen Atom Experiences a Coulomb Force,F $\mu$