When two resistors are connected in parallel across a 12-V battery,6.3 A flows.If the smaller resistor is 2.5 $\varOmega$ how much current flows when the two are put in series across the same battery?

Question

Quizplus · Accepted Answer

When resistors are in parallel, the total current is the sum of the currents through each resistor. Using Ohm's Law (V = IR), the total resistance in parallel can be found using the formula: 1/R_total = 1/R1 + 1/R2. Given the total current is 6.3 A and the voltage is 12 V, the total resistance in parallel is R_total = V/I = 12/6.3 = 1.9 Ω. Since one resistor is 2.5 Ω, the other resistor can be found using the parallel resistance formula, which gives approximately 4.75 Ω. When in series, the total resistance is the sum: 2.5 + 4.75 = 7.25 Ω. The current in series is then I = V/R_total = 12/7.25 = 1.1 A.

When Two Resistors Are Connected in Parallel Across a 12-V Ω\varOmegaΩ

When Two Resistors Are Connected in Parallel Across a 12-V $\varOmega$