A 9.0000-V battery is used to produce a current through two identical resistors in series,each having a resistance of 150.00 kΏ.A handheld digital multimeter (DMM)is used to measure the potential difference across the first resistor by placing probe leads at each end of this resistor.Typical DMMs have an internal resistance of 10 M$\varOmega$.What is the potential difference that the DMM measures across the first resistor?
A)4.500 V
B)4.467 V
C)4.534 V
D)4.425 V
E)4.628 V

Question

Quizplus · Accepted Answer

The potential difference measured by the DMM is affected by its internal resistance. Using the voltage divider formula, we can calculate the potential difference across the first resistor with the DMM connected as follows:

VDMM = VBattery * R1 / (R1 + RDMM)
where R1 is the resistance of the first resistor (150.00 kΏ) and RDMM is the internal resistance of the DMM (10 MF1F1F1S1F1F1F10).

Plugging in the values, we get:
VDMM = 9.0000 V * 150.00 kΏ / (150.00 kΏ + 10 MF1F1F1S1F1F1F10) = 4.467 V

Therefore, the best choice is B.

A 90000-V Battery Is Used to Produce a Current Through Two