If the magnetic field is in the direction as shown,30 $\circ$ relative to the x-axis,and has a magnitude of 0.12 T,what is the flux through a circular coil lined up to be perpendicular to the x-axis with a diameter of 2.3 cm? A)2.3 Tm² B)4.32 * 10^-5 Tm² C)34.8 Gm² D)8.35 * 10^-4 Gm² E)3900 Tm²

Question

Quizplus · Accepted Answer

The flux through a circular coil perpendicular to the magnetic field is given by:
Φ = B*A*cosθ
where B is the magnetic field, A is the area of the coil (πr²), and θ is the angle between the magnetic field and the plane of the coil (since the coil is perpendicular to the x-axis, θ is 90 degrees).

In this case,
B = 0.12 T
r = 1.15 cm (since the diameter is 2.3 cm)
A = πr² = π(1.15 cm)²

Φ = B*A*cosθ = (0.12 T)(π(1.15 cm)²)(cos 90°)

Φ = 4.32 x 10^-5 Tm² = 4.32 x 10^-5 Wb

So the answer is B, 4.32 x 10^-5 Tm² or Wb.

If the Magnetic Field Is in the Direction as Shown,30 ∘\circ∘

If the Magnetic Field Is in the Direction as Shown,30^$\circ$