The figure shows the current through an inductor.If the maximum magnitude of the potential difference $\Delta$V_L across the inductor over the period shown is 60 V,what is the inductance of the inductor? A)100 mH B)1 mH C)10 mH D)1 H

Question

Quizplus · Accepted Answer

The potential difference across an inductor is given by the equation 𝑉𝐿=𝐿(d𝐼/𝑑𝑡), where V_L is the potential difference across the inductor and 𝐿 is the inductance. From the graph, we can see that the maximum rate of change of current is 150 mA/ms (from time t=0.3 s to t=0.4 s). Therefore, the maximum potential difference across the inductor is 𝑉𝐿=𝐿(d𝐼/𝑑𝑡) = 𝐿(0.15/0.001) = 150𝐿 mV. Given that the maximum potential difference across the inductor is 60 V, we can solve for 𝐿 as follows:
60 V = 150𝐿 mV 
L = 0.4 H = 400 mH 
The closest option is C, which is 10 mH.

The Figure Shows the Current Through an Inductor Δ\DeltaΔ VL Across the Inductor Over the Period Shown Is 60

The Figure Shows the Current Through an Inductor $\Delta$ V_L Across the Inductor Over the Period Shown Is 60