An object 2.0 cm high is projected onto a screen using a converging lens with a focal length of 35 cm.The image on the screen is 34 cm high.What is the distance of the lens from the screen? A)1.8 * 10² cm B)6.3 * 10² cm C)1.8 * 10³ cm D)5.6 * 10³ cm E)1.0 * 10³ cm

Question

Quizplus · Accepted Answer

The magnification (m) of the lens is given by the ratio of the image height to the object height, $m = \frac{34}{2} = 17$. The lens formula is $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$, where $f$ is the focal length, $v$ is the image distance, and $u$ is the object distance. The magnification is also given by $m = -\frac{v}{u}$. Using $m = 17$ and $f = 35$ cm, we can solve for $v$ and then find the distance from the lens to the screen. The correct calculation leads to a distance that matches option B, considering the correct use of formulas and units.

An Object 2