A 50-meter spaceship (as measured in the rest frame)is travelling at 0.6c relative to a stationary observer.How long does the spaceship appear to the stationary observer?
A)35 m
B)40 m
C)45 m
D)55 m
E)60 m

Question

Quizplus · Accepted Answer

The length contraction formula is L = L₀√(1-v²/c²). Here, L₀ = 50 m, v = 0.6c. Plugging in the values, L = 50√(1-(0.6)²) = 50√(0.64) = 50 * 0.8 = 40 m.

A 50-Meter Spaceship (As Measured in the Rest Frame)is Travelling