If the energy of the orbiting electron in a hydrogen atom is -9.93 * 10^-3 eV,what is its quantum number? A)37 B)45 C)98 D)1370

Question

Quizplus · Accepted Answer

The energy of an electron in a hydrogen atom is given by the formula $E_n = \frac{-13.6 \text{ eV}}{n^2}$, where $n$ is the principal quantum number. Rearranging the formula to solve for $n$, we get $n = \sqrt{\frac{-13.6 \text{ eV}}{E_n}}$. Substituting $E_n = -9.93 \times 10^{-3} \text{ eV}$ into the formula gives $n = \sqrt{\frac{-13.6}{-9.93 \times 10^{-3}}} \approx 37$.

If the Energy of the Orbiting Electron in a Hydrogen