The differential scattering cross section for particles to scatter by 60 $\circ$ off a 1 mm² area target is 1.5 * 10^-¹⁸ m²/sr.A detector with an area of 2.0 cm² is placed 1.0 m away from the target in order to detect particles that have been scattered at 60 $\circ$ .If 2 * 10¹⁸ particles hit the target every second,how many will strike the detector every second? A)100 B)300 C)600 D)1000 E)2000

Question

Quizplus · Accepted Answer

The number of particles that hit the detector every second can be calculated using the formula:

Number of particles detected = Incident flux x Target area x Scattering cross section x Solid angle ÷ (Distance from target)²

Substituting the given values, we get:

Number of particles detected = 2.0 x 10^-4 m^-2 s^-1 x 10^-12 m^2 x 1.5 x 10^-25 m^2 sr^-1 x (π/3) ÷ 1.0^2

Number of particles detected = 600 s^-1

Therefore, the answer is choice C.

The Differential Scattering Cross Section for Particles to Scatter by 60