An alpha particle (mass = 6.68 × 10−²⁷ kg)is emitted from a radioactive nucleus with a kinetic energy of 4.55 MeV.How fast is the alpha particle moving in m/s? (1 MeV = 1.6 × 10−¹³ J) A)3.84E+3 m/s B)1.48E+7 m/s C)1.04E+7 m/s D)3.82E+7 m/s E)5.11E+6 m/s

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Quizplus · Accepted Answer

To find the velocity of the alpha particle, use the kinetic energy formula: $KE = \frac{1}{2}mv^2$. Rearrange to solve for $v$: $v = \sqrt{\frac{2KE}{m}}$. Given $KE = 4.55 \, \text{MeV} = 4.55 \times 10^6 \times 1.6 \times 10^{-19} \, \text{J}$ and $m = 6.68 \times 10^{-27} \, \text{kg}$, substitute these values to find $v$.

An Alpha Particle (Mass = 6