If a quantum of radiation has an energy of 2.10 keV,what is its wavelength? (h = 6.63 × 10−³⁴ J⋅s,1 eV = 1.60 × 10−¹⁹ J,c = 3.00 × 10⁸ m/s,and 1 nm = 10−⁹ m) A)0.95 nm B)197 nm C)0.59 nm D)1.24 nm E)0.14 nm

Question

Quizplus · Accepted Answer

The energy of a photon can be related to its wavelength using the equation:

E = hc/λ

where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

Rearranging this equation to solve for λ, we get:

λ = hc/E

Plugging in the given values, we get:

λ = (6.63 × 10^-34 J·s) × (3.00 × 10^8 m/s) / (2.10 × 10^3 eV × 1.60 × 10^-19 J/eV)

λ = 0.589 nm

Converting nanometers to meters, we get:

λ = 5.89 × 10^-10 m

Therefore, the correct choice is C) 0.59 nm.

If a Quantum of Radiation Has an Energy of 2